It’s been awhile since we took a look at an SAT word problem! Let’s try one out today!

**Three types of pencils J, K, and L cost $0.05, $0.10, and $0.25. If a box of 32 of these pencils costs a total of $3.40 and if there are twice as many K pencils as L pencils in the box, how many J pencils are there?**

**A) 6**

** B) 12**

** C) 14**

** D) 18**

** E) 20**

—

.05j + .10k + .25l = $3.40

j + k + l = 32

2l = k

Plug the third equation into the 1st and 2nd equations and simplify:

.05j + .2l + .25l = 3.40

.05j + .45l = 3.40

5j + 45l = 340

j + 9l = 68

j + 2l + l = 32

j + 3l = 32

Now we have two equations with two variables. We can solve for j.

j + 9l = 68

– (j + 3l = 32)

6l = 36

l = 6

Plug l back in to solve for j.

j + 9(6) = 68

j + 54 = 68

j = 14

The answer is (C).

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